Cable wrap magnetisation
Wrapping the output cable of a portable unit several times around a part turns the cable into an encircling coil, producing a longitudinal field along the wrapped axis. It is the standard way to magnetise a shaft, a pipe section or a large weldment in the field, where no fixed coil bench exists. Because the turns lie directly on the part, the arrangement is a high fill factor coil: the cable is essentially in contact with the surface, so the flux does not have to spread across an oversized bore.
The field is set by ampere-turns, so wrapping more turns lets a small portable set reach the required magnetomotive force at a current it can actually deliver. Five turns at 1 000 A is the same 5 000 ampere-turns as one turn at 5 000 A, which no portable unit will supply. The demagnetising field from the part’s own end poles still governs how many ampere-turns are needed, hence the length-to-diameter ratio in the formula and its 2 to 15 validity band.
The usual field mistake is treating one wrap as covering the whole part. A coil’s field is only usefully strong for about 230 mm (9 in.) either side of the windings, so a long shaft must be wrapped, shot, unwrapped and re-wrapped further along with overlap. Turns should be kept tight against each other rather than spread out, since a spread wrap behaves like several weak coils instead of one strong one.
Cable heating is the practical limit. Wrapped cable cannot shed heat the way a straight run can, so keep shots short, respect the duty cycle of the set, and check the cable rating against the calculated current before starting.
Worked example
| Part length | 500 mm |
| Part diameter | 100 mm |
| Cable turns | 5 |
| Cable diameter | 20 mm |
| Cable current rating | 1500 A |
| L/D used | 5 |
| Required ampere-turns | 5000 A-turn |
| Cable current | 1000 A |
| Current, lower tolerance | 900 A |
| Current, upper tolerance | 1100 A |
| Wrap positions along the part | 2 |
| Cable used per wrap | 1885 mm |
A 500 mm long, 100 mm diameter shaft with five tight turns of 20 mm cable. L/D = 500/100 = 5. Cable wrap is high fill factor, so NI = 35 000/(5+2) = 5 000 ampere-turns. Over 5 turns the set is run at 5 000/5 = 1 000 A, ±10% giving 900 to 1 100 A. Each wrap is effective 230 mm either side, i.e. 460 mm, so a 500 mm part needs 2 overlapping positions. Cable used = 5 x pi x (100 + 20) = 5 x 376.99 = 1 885 mm, plus leads.
Use at your own risk — verify before you act
These calculators support, and never replace, the judgement of qualified NDT and engineering personnel. Results are provided as is, without warranty of any kind, express or implied, and must be independently verified against the governing code edition named in your contract before being used in any inspection, acceptance, rejection, radiation-safety or fitness-for-service decision. By using them you accept full responsibility for how the results are applied; NDT Inspect, its owners and contributors accept no liability for any loss, damage, injury or death arising from their use or from reliance on them. If a result matters to safety, check it by hand and have it reviewed by a competent person.