Minimum required thickness — ASME VIII UG-27 and B31.3

Remaining life means nothing without a target. The minimum required thickness is the wall the pressure design actually needs — not the nominal wall, and not the nominal wall minus the corrosion allowance, which is a purchasing decision rather than a design limit.

For a cylindrical shell under internal pressure, ASME VIII Division 1 UG-27 gives two thicknesses and the larger governs. Circumferential stress, resisted by the longitudinal seam, needs t = PR/(SE − 0.6P). Longitudinal stress, resisted by the circumferential seam, needs only t = PR/(2SE + 0.4P) — roughly half — which is why a cylinder that fails by internal pressure splits along its length. R is the inside radius in the corroded condition, so it grows as the wall thins.

ASME B31.3 works from the outside diameter instead: t = PD/(2(SEW + PY)), where Y is a coefficient from Table 304.1.1 that accounts for the through-wall stress distribution, W is the weld joint strength reduction factor for elevated temperature, and E is the quality factor for the pipe itself. The pressure design thickness is then increased by mechanical, corrosion and erosion allowances to give the minimum wall to order, but for a fitness assessment it is the pressure design thickness that the measured wall must beat.

Two things dominate the answer and neither comes from ultrasonics. The allowable stress S must be read from ASME Section II Part D at the design temperature, and the joint efficiency E must match the actual radiography of the seam. Both are engineering inputs, and a minimum thickness quoted without stating them is not a number anyone can check.

The formulas here cover thin-wall internal pressure only. External pressure, structural minima, discontinuities, nozzle reinforcement, wind and seismic loading and localised metal loss all sit outside them and are handled by their own rules or by a fitness-for-service assessment.

Worked example

Design ruleb313_straight
Design pressure3 MPa
Outside diameter168.3 mm
Measured wall thickness7.11 mm
Allowable stress137.9 MPa
Joint efficiency / quality factor E1
Weld joint strength reduction factor W1
Coefficient Yauto
Material class for Yferritic
Design temperature100 °C
Manual Y0.4
Corrosion and mechanical allowance1.6 mm
Inside radius (corroded)77.04 mm
Coefficient Y in use0.4
Pressure design thickness1.81 mm
Minimum wall including allowance3.41 mm
Wall above the minimum3.7 mm
MAWP at the measured wall12.06 MPa

NPS 6 Schedule 40 pipe, 168.3 mm OD measured at 7.11 mm, 3.0 MPa design, S = 137.9 MPa, E = W = 1.0, ferritic at 100 °C so Y = 0.4 from Table 304.1.1. t = 3.0 × 168.3 / (2 × (137.9 + 3.0 × 0.4)) = 504.9 / 278.2 = 1.81 mm. With a 1.6 mm allowance the minimum wall is 3.41 mm, leaving 3.70 mm of margin. Rearranged for pressure, the measured 7.11 mm wall is good for 2 × 137.9 × 7.11 / (168.3 − 2 × 0.4 × 7.11) = 12.06 MPa.

Use at your own risk — verify before you act

These calculators support, and never replace, the judgement of qualified NDT and engineering personnel. Results are provided as is, without warranty of any kind, express or implied, and must be independently verified against the governing code edition named in your contract before being used in any inspection, acceptance, rejection, radiation-safety or fitness-for-service decision. By using them you accept full responsibility for how the results are applied; NDT Inspect, its owners and contributors accept no liability for any loss, damage, injury or death arising from their use or from reliance on them. If a result matters to safety, check it by hand and have it reviewed by a competent person.

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