Tracer gas leak rate correction
A leak test almost never uses the service fluid. Helium is used because a mass spectrometer can see it, and the acceptance criterion is usually written for air, nitrogen or the process gas. The two rates are not the same number, and which correction applies depends on how the gas moves through the leak channel.
For very small leaks the channel is narrower than the mean free path of the gas, so molecules pass one at a time without colliding with each other — molecular flow. The throughput then depends on molecular speed, which goes as the inverse square root of molar mass: Q₁/Q₂ = √(M₂/M₁). Helium (M = 4.003) therefore passes about √(28.96/4.003) = 2.69 times faster than air through the same molecular leak. A helium rate must be divided by 2.69 to give the equivalent air rate, and an air-based acceptance limit must be multiplied by 2.69 before it is applied to a helium reading — getting that direction backwards is a factor of seven error.
For larger leaks the channel is wide compared with the mean free path and the flow is viscous (laminar). Throughput is then governed by viscosity, Q₁/Q₂ = η₂/η₁, and the ranking reverses: helium is more viscous than air (about 19.9 versus 18.5 µPa·s at 25 °C), so helium actually passes slightly more slowly than air, by roughly 8%. The molecular relation is the conservative one for the small leaks that matter in vacuum and pressure-equipment work, and is the correction assumed by most codes; the crossover sits broadly around 10⁻⁴ to 10⁻⁵ mbar·L/s, and in the transition region neither law is exact.
Two limitations worth stating on the report. The correction assumes the same pressure difference across the leak in both cases — it does not convert between test pressure and service pressure. And it assumes a clean, dry, open channel; real leak paths that are wetted, blocked by product, or contain a liquid seal behave in neither regime.
Worked example
| Measured leak rate with the test gas | 1 mbar.L/s |
| Test gas (as measured) | helium |
| Service gas (required) | air |
| Flow regime | molecular |
| Conversion factor (service / test) | 0.3718 |
| Equivalent leak rate, service gas | 0.3718 mbar.L/s |
| Reverse factor (test / service) | 2.69 |
| Equivalent rate, viscous law | 1.076 mbar.L/s |
Molecular flow: √(M_He/M_air) = √(4.003/28.96) = √0.138225 = 0.37179, so 1 mbar·L/s of helium is 0.3718 mbar·L/s of air. The reverse factor is 1/0.37179 = 2.690, the familiar helium-to-air factor of 2.69. Under the viscous law the same leak would give 1 x 19.9/18.5 = 1.076 mbar·L/s of air, in the opposite direction — which is why the regime must be stated.