Cable wrap magnetisation
Wrapping the output cable of a portable unit several times around a part turns the cable into an encircling coil, producing a longitudinal field along the wrapped axis. It is the standard way to magnetise a shaft, a pipe section or a large weldment in the field, where no fixed coil bench exists. Because the turns lie directly on the part, the arrangement is a high fill factor coil: the cable is essentially in contact with the surface, so the flux does not have to spread across an oversized bore.
The field is set by ampere-turns, so wrapping more turns lets a small portable set reach the required magnetomotive force at a current it can actually deliver. Five turns at 1 000 A is the same 5 000 ampere-turns as one turn at 5 000 A, which no portable unit will supply. The demagnetising field from the part’s own end poles still governs how many ampere-turns are needed, hence the length-to-diameter ratio in the formula and its 2 to 15 validity band.
The usual field mistake is treating one wrap as covering the whole part. A coil’s field is only usefully strong for about 230 mm (9 in.) either side of the windings, so a long shaft must be wrapped, shot, unwrapped and re-wrapped further along with overlap. Turns should be kept tight against each other rather than spread out, since a spread wrap behaves like several weak coils instead of one strong one.
Cable heating is the practical limit. Wrapped cable cannot shed heat the way a straight run can, so keep shots short, respect the duty cycle of the set, and check the cable rating against the calculated current before starting.
Worked example
| Part length | 500 mm |
| Part diameter | 100 mm |
| Cable turns | 5 |
| Cable diameter | 20 mm |
| Cable current rating | 1500 A |
| L/D used | 5 |
| Required ampere-turns | 5000 A-turn |
| Cable current | 1000 A |
| Current, lower tolerance | 900 A |
| Current, upper tolerance | 1100 A |
| Wrap positions along the part | 2 |
| Cable used per wrap | 1885 mm |
A 500 mm long, 100 mm diameter shaft with five tight turns of 20 mm cable. L/D = 500/100 = 5. Cable wrap is high fill factor, so NI = 35 000/(5+2) = 5 000 ampere-turns. Over 5 turns the set is run at 5 000/5 = 1 000 A, ±10% giving 900 to 1 100 A. Each wrap is effective 230 mm either side, i.e. 460 mm, so a 500 mm part needs 2 overlapping positions. Cable used = 5 x pi x (100 + 20) = 5 x 376.99 = 1 885 mm, plus leads.